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## The battery is now disconnected from the plates and the separation of the plates is doubled ( = 0.78 cm). What is the energy stored in this

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## Answers ( )

Answer:The energy stored in this new capacitor is

Explanation:Suppose, Two parallel plates, each having area A = 2180 cm² are connected to the terminals of a battery of voltage as shown. The plates are separated by a distance d = 0.39 cm.

We need to calculate the chargeUsing formula of capacitancePut the value into the formula

The distance between the plates is doubled.

We need to calculate the new capacitanceUsing formula of capacitancePut the value into the formula

We need to calculate the energy stored in this new capacitorUsing formula of energyPut the value into the formula

Hence, The energy stored in this new capacitor is